College Math Placement Practice Test 2025 - Free College Math Questions and Study Guide

Question: 1 / 400

If a polynomial P(x) has roots at x = 2 and x = -3, what is one possible factorization of P(x)?

P(x) = k(x - 2)(x + 3)

To understand why the first choice is a valid factorization of the polynomial P(x), let's recall how the roots of a polynomial relate to its factors. If a polynomial has roots at x = 2 and x = -3, this means that the polynomial will equal zero at these points.

For the root x = 2, the corresponding factor is (x - 2), because when you substitute 2 into the polynomial, it should yield zero: P(2) = k(2 - 2)(2 + 3) = 0.

For the root x = -3, the corresponding factor is (x + 3), which similarly satisfies the condition that when we substitute -3, the polynomial equals zero: P(-3) = k(-3 - 2)(-3 + 3) = 0.

Thus, by multiplying these factors together and including a non-zero constant k (which can be any real number to stretch or compress the polynomial vertically without altering the roots), we get P(x) = k(x - 2)(x + 3).

The other answer choices do not reflect the correct roots based on the required factors. Therefore, the factorization in the first choice accurately describes

Get further explanation with Examzify DeepDiveBeta

P(x) = k(x + 2)(x - 3)

P(x) = k(x - 2)(x - 3)

P(x) = k(x + 2)(x + 3)

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